函数y=x-ex的单增凸区间是____.
(-∞,0) 分析:y′=1-ex,y′′=-ex,当x>0时,y′<0而x<0时y′>0,所以(-∞,0)为单增区间;又对一切x有y′′<0,所以y=x-ex为凸函数.因此(-∞,0)为单增凸区间.
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