令F(x):x是实数,G(x):x是有理数。命题“实数不全是有理数”的符号化形式为
A.∀x(F(x)→G(x))
B.∀x(F(x)∧G(x))
C.¬∀x(F(x)→G(x))
D.¬∀x(F(x)∧G(x))
正确答案是C
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