设L是以O(0,0)、A(1,0)、B(1,1)为顶点的折线,则∫OAB(x+y)dx=____.
1/2解析:由于线段OA为y=0,0≤x≤1;线段AB为X=1,0≤y≤1,所以∫OAB(x+y)dx=∫OA(x+y)dx+∫AB(x+y)dx=∫01(x+0)dx+∫01(1+y)•0•dy=(1/2)x2∣01+0=1/2
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