计算对弧长的曲线积分∫L(2x-y+1)ds,其中L是直线y=x-1上点(0,-1)到点(1,0)的直线段.
原式=∫01[2x-(x-1)+1]√2dx =√2∫01(x+2)dx=√2/2[(x+2)2]01 =(5/2)√2.
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