设X~N(5,9),已知标准正态分布函数值Φ(0.5)=0.6915,为使P{X﹤a)﹤0.6915,则常数a﹤____.
6.5 。解析:P{X﹤a}=Φ[(a-5)/3]﹤0.6915=Φ(0.5) ∴(a-5)/3﹤0.5.∴a﹤6.5
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