已知函数f(x)的定义域为[0,1],则函数f(x2)的定义域为____.
[-1,1])。 因函数f(x)的定义域为[0,1],故x2∈[0,1],即0≤x2≤1,得-1≤x≤1,所以[-1,1]为所求定义域.
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